196x^2+56x-60=0

Solution for 196x^2+56x-60=0 equation:

196x^2+56x-60=0

a = 196; b = 56; c = -60;
Δ = b2-4ac
Δ = 562-4·196·(-60)
Δ = 50176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{50176}=224$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-224}{2*196}=\frac{-280}{392}
=-5/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+224}{2*196}=\frac{168}{392}
=3/7
$